Your just supposed to put in however much fuel you think you need.
Hello Defendi,
Thank-you for putting the missing piece of the puzzle on the table.
That means if I have a TL 25 25-ton vehicle with a 150 kph wheeled drive with a power cost of 0.375 and a 1 ton fuel load the vehicle has a range of 30 x 1 ÷ 0.375 = 80 km. Formula p. 115 (Power per mt = 30) x (mt of fuel = 1) ÷ (power cost p. 101 (Mass = 25 x Speed = 120 kph ÷ 10,000) per hour)
Have I grasped the Range correctly?
The text on p. 115
To determine how many metric tons of fuel are required for the desired range, compare the power cost of the engine to the power provided by fuel.
now seems to make a little more sense using the same basic inputs I think the text means:
Range in km x Engine Power cost/output ÷ Power Provided per Metric ton chart:
A TL 25 25-ton vehicle designed to travel at 150 kph using a wheeled drive has a power cost of 0.375 and is designed to travel 80 km. At TL 25 Chemical fuel provides 30 units of power per metric ton of fuel.
80 x 0.375 ÷ 30 = 30 ÷ 30 = 1 ton of fuel.
How much volume does the fuel take up 1 kiloliter or 25 kiloliters?